EJERCISIO

hallar los cosenos y angulos del vector v=2i,3j,4k y mostrar que cos α² +cos β²+cos y²=1

cos α= v1||a||                                  cos β= v2/||a||                             cos y= v3/||a||


v=2i,3j,4k                                      v=2i,3j,4k                              v=2i,3j,4k
||a||=5.38                                       ||a||=5.3.8                               ||a||=5.38
angulo=56.30                                angulo=56.30                          angulo=56.30
cos α=4.74                                    cos β=4.74                             cos y=4.74